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(x%8)/4=(x+9)/5怎么解答

(x-8)/4=(x+9)/5 解:5(x-8)=4(x+9) 5x-40=4x+36 5x-4x=36+40 x=76 行家正解,不明白可以追问!祝您学习进步 满意请点击下面的【选为满意回答】按钮,O(∩_∩)O谢谢

(x-8)/4=(x+ 9)/5 5(x-8)=4(x+ 9) 5x-40=4x+36 x=76

(x-4)/(x-5)=(x-5+1)/(x-5)=1+(1/(x-5)) 原方程装换为 1+(1/(x-5))+1+(1/(x-9))=1+(1/(x-8))+1+(1/(x-6)) 1/(x-5)+1/(x-9)=1/(x-8)+1/(x-6) 设x-7=y 1/(y+2)+1/(y-2)=1/(y-1)+1/(y+1) 2y/(y*y-4)=2y/(y*y-1) y=0,x=7

(x-4)/(x-5) + (x-8)/(x-9) = (x-5)/(x-6) + (x-7)/(x-8) (x-5+1)/(x-5) + (x-9+1)/(x-9) = (x-6+1)/(x-6) + (x-8+1)/(x-8) 1+1/(x-5) + 1+1/(x-9) = 1+1/(x-6) + 1+1/(x-8) 1/(x-5) + 1/(x-9) = 1/(x-6) + 1/(x-8) 1/(x-9) - 1/(x-8) = 1/(x-6)...

解方程 ( 要过程和检验 ) x-4/9=5/18 x=5/18+4/9 x=13/18 3/8+x=3/4 x=3/4-3/8 x=3/8 5/6-x=1/4 x=5/6-1/4 x=7/12 x+9/10=2 x=2-9/10 x=1.1

x-4)/(x-5)=(x-5+1)/(x-5)=1+(1/(x-5)) 原方程装换为 1+(1/(x-5))+1+(1/(x-9))=1+(1/(x-8))+1+(1/(x-6)) 1/(x-5)+1/(x-9)=1/(x-8)+1/(x-6) 设x-7=y 1/(y+2)+1/(y-2)=1/(y-1)+1/(y+1) 2y/(y*y-4)=2y/(y*y-1) y=0,x=7

(x-4/x-5)+(x-5/x-6)=(x-8/x-9)+(x-7/x-8) -1/x2-11x+30=-1/x2-17x+72 x=7 上面的2是平方

:(x+3)/(x+4)+(x+8)/(x+9)=(x+4)/(x+5)+(x+7)/(x+8) 变为 :(x+3)/(x+4)-(x+4)/(x+5)=(x+7)/(x+8)-(x+8)/(x+9) (x^2+8x+15-x^2-8x-16)/(x+4)(x+5)=(x^2+16x+63-x^2-16x-64)/(x+8)(x+9) -1/(x+4)(x+...

(x-4/x-5)-(x-7/x-8)=(x-5/x-6)-(x-8/x-9)(x-4)/(x-5)+(x-8)/(x-9)=(x-7)/(x-8)+(x-5)/(x-6) 1+1/(x-5)+1+1/(x-9)=1+1/(x-8)+1+1/(x-6) 1/(x-5)+1/(x-9)=1/(x-8)+1/(x-6) 1/(x-5)-1/(x-8)=1/(x-6)-1/(x-9) -3/(x^2-13x+40)=-3/(x^2-15x+54) x^2-...

是matlab代码吧 1:4是从1到4 16就是第16个 5:8是从5到8 9:11是从9到11 12:15是从12到15 简单点说就是将16号位置上的数移到第5位置上。 你如果想看x的值的话就在运行这段代码时将x后面的分号去掉。

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