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2x的平方 4x 1 0

2x平方-4x-1=0 2x^2-4x+2=3 2(x^2-2x+1)=3 2(x-1)^2=3 (x-1)^2=3/2 x-1=±√6/2 x=1±√6/2

2x²-4x+1=0 x²-2x+1=1/2 (x-1)²=1/2 x=1+√2/2 x=1-√2/2

答: 2x²-4x+1=0 2(x²-2x+1)-2+1=0 2(x-1)²=1 (x-1)²=1/2 x-1=±√2 /2 x=1±√2 /2

2x²+4x=1 x²+2x=1/2 x²+2x+1=1/2+1 (x+1)²=3/2 x+1=±√6/2 x=(-2-√6)/2,x=(-2+√6)/2

2x^2-4x+1=0 x^2-2x=-1/2 x^2-2x+1=1/2 (x-1)^2=1/2 x=1+√2/2或x=1-√2/2

4x^2-1=0,所以x^2=1/4,即x=1/2或x=-1/2

2x^2-4x-1=0 b^2-4ac=16-4*2*(-1)=24 x1=(4+根号24)/4=(2+ 根号6)/2 x2=(4-根号24)/4=(2-根号6)/2

-4x²+2x+1=0. (1)配方法: 两边同除以-4,得:x²-(1/2)x-1/4=0. 配方得:x²-(1/2)x+(1/4)²=1/4+(1/4)² 即:(x-1/4)²=5/16. 开方得:x-1/4=±√5/4. 故x1=1/4+√5/4=(1+√5)/4, x2=1/4-√5/4=(1-√5)/4. (2)公式法: b²...

2x²-4x-1=0 2x-4x+2=1+2 2(x-1)²=3 (x-1)²=3/2 x-1=±√(3/2) x=1±(√6)/2 ∴ x=(2±√6)/2

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